4k^2+8k-73=-3

Solution for 4k^2+8k-73=-3 equation:

4k^2+8k-73=-3

We move all terms to the left:

4k^2+8k-73-(-3)=0

We add all the numbers together, and all the variables

4k^2+8k-70=0

a = 4; b = 8; c = -70;
Δ = b2-4ac
Δ = 82-4·4·(-70)
Δ = 1184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1184}=\sqrt{16*74}=\sqrt{16}*\sqrt{74}=4\sqrt{74}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{74}}{2*4}=\frac{-8-4\sqrt{74}}{8}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{74}}{2*4}=\frac{-8+4\sqrt{74}}{8}
$